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Question

sin3A+sin3AsinA+cos3Acos3AcosA

A
\N
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B
1
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C
2
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D
3
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Solution

The correct option is D 3
G.E.=sin3A+3sinA4sin3AsinA+cos3A+4cos3A3cosθcos A=33 sin2A+33 cos2A=3

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