$\frac{\sqrt{441}}{3} \times \frac{\sqrt{225}}{5} \times \frac{64}{\sqrt{256}} = ?$

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Solution

The correct option is D
84

$\frac{21}{3} \times \frac{15}{5} \times \frac{64}{16} = 84$

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Similar questions

9^{2} \times 7^{2} \div \sqrt{441} - 64 = 5^{?}

Q. Factorisation of the expression :

225 x^{5} - 256 x^{3}

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Q. Find the square roots of the followings(i)

\frac{225}{441}

Evaluate: ${(\begin{matrix} \frac{64}{125} \end{matrix})}^{\frac{- 2}{3}} \div \frac{1}{(\frac{256}{625})^{\frac{1}{4}}} + (\begin{matrix} \frac{(\sqrt{25})}{\sqrt[3]{64}} \end{matrix})$

Q. If the ratio of areas of two squares is 225 : 256, then the ratio of their perimeters is

(a) 225 : 256
(b) 256 : 225
(c) 15 : 16
(d) 16 : 15

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√4413×√2255×64√256=?

The correct option is D 84 213×155×6416=84

$\frac{\sqrt{441}}{3} \times \frac{\sqrt{225}}{5} \times \frac{64}{\sqrt{256}} = ?$

The correct option is D
84

$\frac{21}{3} \times \frac{15}{5} \times \frac{64}{16} = 84$