Question

$\frac{tan{35}^o}{cot{55}^o}+\frac{cot{78}^o}{tan{12}^o}$= ?

(a) 0 (b) 1 (c) 3 (d) none of these

Answer 1

$\frac{tan{35}^o}{cot{55}^o}+\frac{cot{78}^o}{tan{12}^o}=\frac{tan{35}^o}{cot({90}^o-{35}^o)}+\frac{cot({90}^o-{12}^o)}{tan{12}^o}=\frac{tan{35}^o}{tan{35}^o}+\frac{tan{12}^o}{tan{12}^o}=1+1=2$