Question

$\frac{tan{55}^{\circ }}{cot{35}^{\circ }}\times sin{30}^{\circ }=A$

The value of 2A is___

Answer 1

$\frac{tan{55}^{\circ }}{cot{35}^{\circ }}\times sin{30}^{\circ }=A\frac{tan{55}^{\circ }}{cot({90}^{\circ }-{55}^{\circ })}\times sin{30}^{\circ }=A\Rightarrow \frac{tan{55}^{\circ }}{tan{55}^{\circ }}\times \frac{1}{2}=A\Rightarrow A=\frac{1}{2}\Rightarrow 2A=1$