Question

$\frac{\tan {65}^o}{\cot {25}^o}=1$
Write 1 for true and 0 for false

Answer 1

$\frac{\tan {65}^{\circ }}{\cot {25}^{\circ }}=\frac{\tan ({90}^{\circ }-{25}^{\circ })}{\cot {25}^{\circ }}=\frac{\cot {25}^{\circ }}{\cot {25}^{\circ }}=1$