Tan35-6-sin11-3-7-3-5-4 -cosec7-4-cos17-6 -

Tan(6π π/6)sin(4π π/3)(2π + π/3)/(π + π/4) cosec(2π π/4) cos(3π π/6) = 1/√(3).( √(3)/2).2/1.( √(2))( √(3)/2) = √(2/3) ...

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Sign of Trigonometric Ratios in Different Quadrants

tan35π/6.sin1...

Question

$\frac{tan (\frac{35 π}{6}) . sin (\frac{11 π}{3}) . sec (\frac{7 π}{3})}{cot (\frac{5 π}{4}) . c o s e c (\frac{7 π}{4}) . cos (\frac{17 π}{6})} =$

\sqrt{\frac{2}{3}}

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- \sqrt{\frac{2}{3}}

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\sqrt{\frac{3}{2}}

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\frac{\sqrt{3}}{2}

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Solution

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Similar questions

\frac{tan (\frac{35 π}{6}) . sin (\frac{11 π}{3}) . sec (\frac{7 π}{3})}{cot (\frac{5 π}{4}) . c o s e c (\frac{7 π}{4}) . cos (\frac{17 π}{6})} =

{sec}^{2} \frac{5 π}{6} + c o s e c \frac{7 π}{6} - cot \frac{3 π}{4}

{(\frac{5 π}{12})}^{\circ}

- {(\frac{7 π}{12})}^{\circ}

\frac{π}{3}

\frac{5 π^{\circ}}{6}

\frac{2 π^{\circ}}{9}

\frac{7 π^{\circ}}{24}

| z | = 4

a r g z = \frac{5 π}{6}

z =

l o g_{1 / 3} \sqrt{x^{2} - 2 x} = s i n \frac{11 π}{6}

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