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Question

sin θ cos (90θ) cos θsin (90θ)+cos θ sin (90θ) sin θcos (90θ)= ___


A

- 1

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B

0

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C

1

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D

2

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Solution

The correct option is C

1


sin θ cos (90θ) cos θsin (90θ)+cos θ sin (90θ) sin θcos (90θ)

=sin θ(sin θ)/cos θ/cos θ+cos θ(cos θ)/sin θ/sin θ

=sin2 θ+cos2 θ

=1


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