|x|−1|x|−2)⩽0|x|isalways⩾0henceonnumberlineinourcase|x|≠2asweneedvaluetobe⩽0hence1⩽|x|<2
In inequality log 1/2(x2-6x+12) ≥ -2 there is one step which says (x-2)(x-4) ≤ 0,. then how can we conclude that x<2 and x>4 ?