$\frac{x^{2} - 10 x + 25}{x^{2} - 25}$ is equal to

\frac{x + 5}{x - 5}

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\frac{x - 5}{x + 5}

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Solution

The correct option is B $\frac{x - 5}{x + 5}$
$\frac{x^{2} - 10 x + 25}{x^{2} - 25} = \frac{(x - 5)^{2}}{(x + 5) (x - 5)} = \frac{x - 5}{x + 5}$

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Similar questions

{x^{2} + 10 x + 25} \div (x + 5)

(x^{2} + 10 x + 25) \div (x + 5)

\frac{x^{2} - 25}{x + 3}

\frac{x + 5}{x^{2} - 9}

If each side of a square is of length

(x + 5) units, then find its area?

f (x) = ⎧ ⎨ ⎩ \begin{matrix} \frac{x^{2} - 25}{x - 5}, w h e n x \neq 5 10, w h e n x = 5 \end{matrix}

x = 5

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