$\frac{(x^{2} - b) (x - a)}{(a - x)}$ =

(b^{2} - x^{2})

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(x^{2} - b)

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(b + x^{2})

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(b - x^{2})

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Solution

The correct option is D $(b - x^{2})$
Given,
$\frac{(x^{2} - b) (x - a)}{(a - x)}$

The denominator of the given expression can be written as $(- 1) (x - a)$ .

So, the given expression will be,
$\frac{(x^{2} - b) (x - a)}{(- 1) (x - a)}$

By cancelling the common terms in numerator and denominator, we get
$\frac{(x^{2} - b)}{(- 1)}$
$= \frac{(- 1) (b - x^{2})}{(- 1)}$
$= (b - x^{2}) .$

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Similar questions

The expansion $(x + a) (x + b)$ is

\frac{(x^{2} - b) (x - a)}{(a - x)}

\frac{x^{2} - x - 1}{x^{3} - 8} = \frac{A}{x - 2} + \frac{B x + C}{x^{2} + 2 x + 4} \Rightarrow A + B =

(x + a) (x + b) = x^{2} + (a + b) x + a b

l i m x \to a (x - a) (\frac{1}{x - a} - \frac{1}{x^{2} - (a + b) x + a b}) =

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