$\frac{x^{3} - 2 x^{2} + 3 x}{x} =$

x^{2} - 2 x + 3

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x^{2} - 2 x^{2} + 3

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x^{3} - 2 x^{2} + 3

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Solution

The correct option is A $x^{2} - 2 x + 3$
Divide all the terms of the expression $x^{3} + 2 x^{2} + 3 x$ separately by $x$ .

$\frac{x^{3}}{x} - \frac{2 x^{2}}{x} + \frac{3 x}{x} = x^{2} - 2 x + 3$ ;

Therefore, $\frac{(x^{3} - 2 x^{2} + 3 x)}{x} = x^{2} - 2 x + 3$

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