Question 24
$\frac{x + y}{2}$ is a rational number
(a) Between x and y
(b) Less than x and y both.
(c) Greater than x and y both.
(d) Less than x but greater than y.

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Solution

Let x and y be two numbers
Case I If x < y
Then, $\frac{x + y}{2}$ lies in between x and y such that

Case II If y < x
Then, $\frac{x + y}{2}$ lies in between x and y such that

Hence, the correct option is (a).

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Question 24
$\frac{x + y}{2}$ is a rational number
(a) Between x and y
(b) Less than x and y both.
(c) Greater than x and y both.
(d) Less than x but greater than y.

If $x$ and $y$ are distinct rational numbers which of the following is true about $\frac{x + y}{2}$ ?

If x and y are distinct integers, which of the following is true about $\frac{x + y}{2}$ ?

In the following question, two equations are given. Solve both the equations and mark the corresponding answer, if:

a) x is greater than y

b) x is less than y

c) x is greater than or equal than y

d) x is less than or equal to y

e) x = y or a definite relationship between x & y cannot be established

2x $^{2}$ + 3x + 1 = 0

12y $^{2}$ + 7y + 1 = 0

In the following question, two equations are given. Solve both the equations and mark the corresponding answer, if:

a) x is greater than y

b) x is less than y

c) x is greater than or equal than y

d) x is less than or equal to y

e) x = y or a definite relationship between x & y cannot be established

I. x $^{2}$ + 4x + 4 = 0

II.y $^{2}$ - 8y + 16 = 0

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Question 24 x+y2 is a rational number (a) Between x and y (b) Less than x and y both. (c) Greater than x and y both. (d) Less than x but greater than y.

Let x and y be two numbers Case I If x < y Then, x+y2 lies in between x and y such that Case II If y < x Then, x+y2 lies in between x and y such that Hence, the correct option is (a).

Question 24
$\frac{x + y}{2}$ is a rational number
(a) Between x and y
(b) Less than x and y both.
(c) Greater than x and y both.
(d) Less than x but greater than y.

Let x and y be two numbers
Case I If x < y
Then, $\frac{x + y}{2}$ lies in between x and y such that

Case II If y < x
Then, $\frac{x + y}{2}$ lies in between x and y such that

Hence, the correct option is (a).