X-y-z-xyz-1-yz-1-xz-1-xy

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Division of a Polynomial by a Monomial

x+y+z/xyz=1/y...

Question

$\frac{x + y + z}{x y z} = \frac{1}{y z} + \frac{1}{x z} + \frac{1}{x y}$

False

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True

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Solution

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Similar questions

If x+y+z=6, xy+xz+yz=11, xyz=6 thenequals

x + y + z = 6, x y + x z + y z = 11, x y z = 6

\frac{x}{y z} + \frac{y}{x z} + \frac{z}{x y}

The value of $52 x y z (x y + y z + x z + y^{2}) (z + x) \times 104 x y (x y + x z + y z + y^{2})$ is:

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + 1 & x y & x z x y & y^{2} + 1 & y z x z & y z & z^{2} + 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = 1 + x^{2} + y^{2} + z^{2} .

Simplify the expression: \frac{52 w x y z (x y + y z + x z + y^{2}) (z + x)}{104 x y (x y z + x z^{2} + y z^{2} + y^{2} z)}

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