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Question

yy−2+1y+2+3y4−y2 = .

A
y22y24
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B
y22y2+2
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C
y+2y2
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D
1y+2
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Solution

The correct option is A y22y24
yy−2+1y+2+3y4−y2
= [y(y+2)+1(y−2)(y−2)(y+2)]+3y4−y2
= y2+3y−2y2−4−3yy2−4
= y2−2y2−4

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