Question

Fraction of total power carried by the side bands $\left(P_S/P_T\right)$ is given by

• A. $m^2$
• B. $\frac{2+m^2}{m^2}$
• C. $\frac{2+m}{m}$
• D. $\frac{m^2}{2+m^2}$

Answer 1

The correct option is D $\frac{m^2}{2+m^2}$

$\text{Explanation:-}$

We know that

Total power, $P_T=2+m^2...........\left(1\right)$

Side band power, $P_S=m^2...............\left(2\right)$

From above equation we get,

$\frac{Sidebandpower}{Totalpower}=\frac{P_S}{P_T}=\frac{m^2}{2+m^2}$

$\text{Hence the correct option is D}$