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Fraction of t...

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Fraction of total power carried by the side bands (PS/PT) is given by m^2 (2+m^2)/m^2 (2+m)/m m^2/(2+m^2)

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Q. In AM wave, total power of side bands is given by:

Q. A body of mass

m_{1}

moving with a velocity

u

collides elastically with another body of mass

m_{2}

at rest.
a) The fraction of kinetic energy transferred to second body is

\frac{4 m_{1} m_{2}}{(m_{1} + m_{2})^{2}}

b) The fraction of energy retained by the first body is

(\frac{m_{1} - m_{2}}{m_{1} + m_{2}})^{2}

m_{1}

=

m_{2}

, then the energy transferred is

100 %

d) The energy lost during the collision is found as heat

Q. Fill in the blanks :
(i) 2

m^{2}

c m^{2}

m^{2}

k m^{2}

m^{2}

m m^{2}

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