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Question

Fractional values of oxidation numbers are possible as in Na2S4O6I, Fe3O4II, N3HIII

A
Only I
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B
Only II
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C
I and III
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D
I, II and III
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Solution

The correct option is D I, II and III
Na2S4O6Fe3O42×1+4x+6(2)=03×x+4(2)=02+4x12=03x8=04x=+103x=8x=+104=+2.5x=+83or+223Average oxidation number ofAverage oxidation number of ironS is +2.5is +223
N3H3x+1=03x=1x=13Average oxidation number ofnitrogen is 13.

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