Frame a formula for the following statement :
The Fahrenheit temperature F decreased by 32 is equal to nine-fifths of the centigrade temperature C.

F + 32 = \frac{9}{5} C

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F - 32 = \frac{5}{9} C

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F - 32 = \frac{9}{5} C

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none of the above

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Solution

The correct option is C $F - 32 = \frac{9}{5} C$
Clearly option C is right.

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Similar questions

Q. The Fahrenheit temperature

F

decreased by

32

is equal to nine-fifths of the centigrade temperature

C

. The correct formula framed for the above statement will be :

F - 32 = \frac{9}{5} C

;

x^{\circ}

is a temperature at which centigrade and Fahrenheit read the same. Find x.

Q. The formula

F = \frac{9}{5} C + 32

relates any Centigrade reading to its corresponding Fahrenheit reading. For what temperature is the reading the same on both scales?

F - 32 = \frac{9}{5} C

Change the subject of the above formula to :
(a) C, (b) F.

A solution is to be kept between $68^{\circ} F$ and $77^{\circ} F$ . What is the range of temperature in degree Celsius (C) if the Celsius /Fahrenheit (F) convension formula is given by $F = \frac{9}{5} C + 32$ ?

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Frame a formula for the following statement :The Fahrenheit temperature F decreased by 32 is equal to nine-fifths of the centigrade temperature C.

The correct option is C F−32=95CClearly option C is right.

Frame a formula for the following statement :
The Fahrenheit temperature F decreased by 32 is equal to nine-fifths of the centigrade temperature C.

The correct option is C $F - 32 = \frac{9}{5} C$
Clearly option C is right.