Frame an algebraic expression for the perimeter of a rectangle whose length is twice its breadth.

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Solution

We know that,

Perimeter of a rectangle $= 2 \times (L e n g t h + B r e a d t h)$

It is given that the length of a rectangle is twice its breadth.
Let the breadth of the rectangle be $x m$ .

So, Breadth $= x$ and Length $= 2 x$

Therefore, Perimeter of rectangle $= 2 \times (2 x + x) = 6 x$

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Frame an algebraic expression for the perimeter of a rectangle whose length is twice its breadth.

We know that, Perimeter of a rectangle =2×(Length+Breadth) It is given that the length of a rectangle is twice its breadth. Let the breadth of the rectangle be x m. So, Breadth =x and Length =2x Therefore, Perimeter of rectangle =2×(2x+x)=6x

We know that,

Perimeter of a rectangle $= 2 \times (L e n g t h + B r e a d t h)$

It is given that the length of a rectangle is twice its breadth.
Let the breadth of the rectangle be $x m$ .

So, Breadth $= x$ and Length $= 2 x$

Therefore, Perimeter of rectangle $= 2 \times (2 x + x) = 6 x$