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Abnormal Colligative Properties

Freezing poin...

Question

Freezing point of $C_{6} H_{6} (l)$ is ${5.5}^{0} C$ . If $10 g$ of $C_{4} H_{10}$ is mixed with $200 g$ of $C_{6} H_{6} (l)$ . Calculate freezing point of solution $k_{f} = {5.12}^{o} C / m .$

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Solution

Ans. $({1.09}^{0} C)$
$Δ T_{f} = k_{f} \times m$

$= 5.12 \times \frac{10}{58} \times \frac{1000}{200} = {4.41}^{0} C$

$Δ T_{F} = {(T_{F})}_{solvent} - {(T_{F_{1}})}_{Solution}$

${4.41}^{0} C = 5.5 - {(T_{F_{1}})}_{Solution}$

${(T_{F_{1}})}_{Solution} = 5.5 - 4.41 = {1.09}^{0} C$

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