CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Abnormal Colligative Properties

Freezing poin...

Question

Freezing point of $C_{6} H_{6} (l)$ is ${5.5}^{0} C$ . If $10 g$ of $C_{4} H_{10}$ is mixed with $200 g$ of $C_{6} H_{6} (l)$ . Calculate freezing point of solution $k_{f} = {5.12}^{o} C / m .$

Open in App

Solution

Ans. $({1.09}^{0} C)$
$Δ T_{f} = k_{f} \times m$

$= 5.12 \times \frac{10}{58} \times \frac{1000}{200} = {4.41}^{0} C$

$Δ T_{F} = {(T_{F})}_{solvent} - {(T_{F_{1}})}_{Solution}$

${4.41}^{0} C = 5.5 - {(T_{F_{1}})}_{Solution}$

${(T_{F_{1}})}_{Solution} = 5.5 - 4.41 = {1.09}^{0} C$

Suggest Corrections

thumbs-up

0

Similar questions

If enthalpy of hydrogenation of

C_{6} H_{6} (l)

C_{6} H_{12} (l)

- 205 k J

and resonance energy of

C_{6} H_{6} (l)

- 152 k J / m o l

then enthalpy of hydrogenation of the given figure is
[Assume :

Δ H_{v a p}

C_{6} H_{6} (l), C_{6} H_{8} (l), C_{6} H_{12} (l)

Q. Benzene burns in oxygen according to the following reaction :

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to {3 H}_{2} O (l) + {6 C O}_{2} (g)

If the standard enthalpies of formation of

C_{6} H_{6} (l)

H_{2} O (l)

{C O}_{2} (g)

are 11.7, -68.1 and -94 kcal/mole, respectively, the amount of heat that will liberate burning 780 g benzene is:

Q. The standard enthalpies of combustion of

C_{6} H_{6} (l),

C_{(g r a p h i t e)}

H_{2} (g)

are respectively

- 3270

k J

{m o l}^{- 1},

- 394

k J

{m o l}^{- 1}

- 286

k J

{m o l}^{- 1}

. What is the standard enthalpy of formation of

C_{6} H_{6} (l)

k J

{m o l}^{- 1}

?

Q. The freezing point depression constant for water is

{1.86}^{o} C

m^{- 1}

5

N a_{2} S O_{4}

is dissolved in 45 g

H_{2} O

, the freezing point is changed by

- {3.82}^{o} C

Calculate the van't Hoff factor for

N a_{2} S O_{4}

Q. The freezing point of

0.02

mol fraction of acetic acid in benzene is

277.4 K

. Acetic acid exists partly as a dimer. Calculate the equilibrium constant for dimerization. (approximately)
(Freezing point of

C_{6} H_{6} = 278.4 K

K_{f}

C_{6} H_{6} = 5 K m^{- 1}

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Abnormal Colligative Properties

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Abnormal Colligative Properties

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon