Question

Freezing point of ethyl alcohol is 156 K which is equal to:

• A. $-{217}^{\circ }C$
• B. $-{145}^{\circ }C$
• C. $-{120}^{\circ }C$
• D. $-{117}^{\circ }C$

Answer 1

The correct option is D $-{117}^{\circ }C$

Given, temperature in Kelvin scale, $K=156K$.
Let $K$ be the temperature in Kelvin scale and $C$ be the temperature in Celsius scale.
We know, $K=273+C$
$\Rightarrow 156=273+C$
$\Rightarrow C=156-273=-{117}^{\circ }C$