Frequency of a pendulum depends on

length of the pendulum

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acceleration due to gravity

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mass of the pendulum

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All of the above

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Solution

The correct options are
A acceleration due to gravity
D length of the pendulum
The formula for time period of a pendulum is $T =$ $2 \times Π \times \sqrt{(} \frac{L}{g})$ . Where $T$ is its period, $L$ is the length of the pendulum and $g$ is the acceleration due to gravity. It depends only on $L$ and $g$ .

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Similar questions

Q. Assertion :The frequency of a seconds pendulum in an elevator moving up with an
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Q. Natural frequency of simple pendulum depends upon:

A simple pendulum is taken to a place where the acceleration due to gravity falls to one-fourth. The time period of the pendulum becomes ___ its initial value.

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Frequency of a pendulum depends on

The correct options are A acceleration due to gravity D length of the pendulumThe formula for time period of a pendulum is T= 2×Π×√(Lg). Where T is its period, L is the length of the pendulum and g is the acceleration due to gravity. It depends only on L and g.