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Question

Frequency of tuning fork A is 256 Hz. It produces four beats/sec with tuning fork B. When wax is applied at tuning fork B then 6 beats/sec are heard. By reducing little amount of wax 4 beats/sec are heard. Frequency of B is :

A
250 Hz
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B
252 Hz
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C
260 Hz
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D
256 Hz
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Solution

The correct option is B 252 Hz

Let the unknown frequency of the tuning fork be x.

So, according to the given data when no waxed, its frequency must be,

x=256±4 to produced a beat of 4 beats/sec.

We know, the frequency of a tuning fork decreases as it is waxed.

So, to produce 6 beats/s, after being waxed, the frequency of the tuning fork must be

x=2564

x=252Hz

Hence, the frequency of B is 252 Hz


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