Frequency of tuning fork A is 256 Hz. It produces four beats/sec with tuning fork B. When wax is applied at tuning fork B then 6 beats/sec are heard. By reducing little amount of wax 4 beats/sec are heard. Frequency of B is :
Let the unknown frequency of the tuning fork be x.
So, according to the given data when no waxed, its frequency must be,
x=256±4 to produced a beat of 4 beats/sec.
We know, the frequency of a tuning fork decreases as it is waxed.
So, to produce 6 beats/s, after being waxed, the frequency of the tuning fork must be
x=256−4
x=252Hz
Hence, the frequency of B is 252 Hz