CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Frequency of tuning fork A is 256 Hz. It produces four beats/sec with tuning fork B. When wax is applied at tuning fork B then 6 beats/sec are heard. By reducing little amount of wax 4 beats/sec are heard. Frequency of B is :

A
250 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
252 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
260 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
256 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 252 Hz

Let the unknown frequency of the tuning fork be x.

So, according to the given data when no waxed, its frequency must be,

x=256±4 to produced a beat of 4 beats/sec.

We know, the frequency of a tuning fork decreases as it is waxed.

So, to produce 6 beats/s, after being waxed, the frequency of the tuning fork must be

x=2564

x=252Hz

Hence, the frequency of B is 252 Hz


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Apparent Frequency
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon