Question

Freshly prepared pure dilute solution of sodium in liquid ammonia :

• A. shows copper-bronze colour.
• B. occupy larger volume than that from the sum of the volumes of $Na$ and $N{H}_3\left(1\right)$.
• C. reduced the $Ge{H}_4$ to $Ge{H}_2^{-}$.
• D. produced sodium amide and hydrogen gas with rusty iron wire.

Answer 1

Answer: (A), (D)

The correct options are
A shows copper-bronze colour.
D produced sodium amide and hydrogen gas with rusty iron wire.

In dilute solutions of $Na$ in ammonia, the solvated electrons have a deep blue colour.

In more concentrated solutions, the solution takes on a bronze/copper colour.

The solution of sodium in liquid ammonia is quite stable on its own.

You need to add a small amount of a catalyst such as ${FeCl}_3$ for the sodium to react with the ammonia to form sodium amide and hydrogen gas.

$2N{a}_{\left(s\right)}+2N{H}_{3\left(l\right)}\underrightarrow{FeC{l}_3}2NaN{H}_2\left(N{H}_3\right)+H_{2\left(g\right)}$
conclusion : hence the option (A) and(D) is correct.