Friction force on 6 kg block is :

12 N

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8 N

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6 N

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4 N

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Solution

The correct option is B $8 N$
Before calculating the the force of friction on 6kg block, in block of 4 kg and 2 kg the friction force will be as follows :

$μ = 0.2; m = 2 k g$
Normal force $F_{n} = m g = 2 \times 10 = 20 N$
$F r i c t i o n F o r c e F_{f} = μ F_{n} = 0.2 \times 20 = 4 N$

Similarly,
$μ = 0.2; m = 4 k g$
Normal force $F_{n} = m g = 4 \times 10 = 40 N$

$F r i c t i o n F o r c e F_{f} = μ F_{n} = 0.2 \times 40 = 8 N$

Total force F $= 20 N$
So,the friction force in 6kg block $i s = 20 - (8 + 4) = 8 N$

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