Solving Linear Differential Equations of First Order
From 0,0 , a ...
Question
From (0,0), a tangent is drawn to the curve y=ex. Then the area bounded by the tangent, y=ex and y−axis is
A
2e
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B
e
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C
e2
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D
e2−1
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Solution
The correct option is De2−1
Let (a,ea) be the point where tangent touches y=ex.
Then slope at (a,ea) is ea
Equation of tangent at (a,ea) is (y−ea)=ea(x−a)
But the tangent passes through (0,0) ⇒a=1
So, equation of tangent is y=ex
Required area =1∫0(ex−ex)dx =[ex−ex22]10=(e−e2)−e0=e2−1