Question

From $160g$ sample of $S{O}_2,1.2046\times {10}^{24}$ atoms are removed, find the volume of remaining $S{O}_2$ at STP.

• A. $11.2litre$
• B. $12.2litre$
• C. $5.2litre$
• D. $15.4litre$

Answer 1

Answer: (A)

$11.2litre$

Moles of $S{O}_2$ = $160$/$64$=$2.5$ mole

Total number of atoms= number of moles*Avogadro's number

= $2.5$*$6.022$*${10}^{23}$

If $1.2046$*$10$^$24$ atoms are removed

Then,

Remaining atoms = $1.5055$*${10}^{24}$ - $1.2046$*${10}^{24}$

= $0.301$*${10}^{24}$ atoms

Remaining moles = $0.301$*${10}^{24}$ / $6.022$*${10}^{23}$

= $0.5$ moles

$1$ mole of $S{O}_2$ is containing $22.4$ L volume.

So

$0.5$ mole of $S{O}_2$ is containing $11.2$ L volume.