Question

From $3$ coconuts, $4$ apples and $2$ oranges, how many selections of fruit can be made, taking at least one of each kind?

• A. $215$
• B. $315$
• C. $415$
• D. None of the above

Answer 1

Answer: (B)

$315$

The ways of choosing at least one coconut =$\left(2^3\right)-1=7$
The ways of choosing at least one apple = $\left(2^4\right)-1=15$
and for orange $\left(2^2\right)-1=3$
So total number of ways is $7\times 15\times 3=315$