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Concentration Terms

From 392 mg o...

Question

From 392 mg of H2SO4 , 1.204 *10^21 molecules are removed. How many moles are left ?

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Solution

Dear student,

No.ofmoles = $fraction numerator W space t over denominator M o l. space w t. end fraction space o r space space space fraction numerator space N o. space space space o f space space space m o l e c u l e s over denominator N end fraction space$

Taking molecular weight of = 98 g

number of moles of 392g =

=

=0.004 mol __________________(1)

Now,

1.204 × molecules =

$fraction numerator 1.204 cross times 10 to the power of 21 over denominator 6.022 cross times 10 to the power of 23 end fraction equals 0.1999 cross times 10 to the power of negative 2 end exponent equals 0.001999 space m o l space space space space space space _ _ _ _ _ _ _ _ _ _ _ _ _ _ left parenthesis 2 right parenthesis$

Now,

Moles left= (1) - (2)

= 0.004 - 0.001999

= 0.002001

So (approx.) 0.002 moles remaining

Regards

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