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Byju's Answer
Standard XII
Mathematics
Permutation: n Different Things Taken All at a Time When All Are Not Different.
From 5 cons...
Question
From
5
consonants and
4
vowels, how many words can be formed using
3
consonants and
2
vowels?
A
9440
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B
6800
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C
3600
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D
7200
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Solution
The correct option is
D
7200
From
5
consonants and
4
vowels , we have to select
3
consonant and
2
vowel.
The no of alphabets in new word would be
5
. Those
5
can be arranged within themselves.
Therefore ,
5
C
3
×
4
C
2
×
5
!
=
7200
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Permutation: n Different Things Taken All at a Time When All Are Not Different.
Standard XII Mathematics
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