From a $10.5$ metre rod, an $8.05$ centimetre piece is cut off. What is the length of the remaining piece?

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Solution

We know that $1 m = 100 c m$
Length of the rod $= 10.5 m = 10.5 \times 100 = 1, 050 ‬ c m$
Piece of rod cut off=8.05\ cm$
Remaining rod $= 1050 - 8.05 = 1, 041.95 ‬ c m$
$= \frac{1041.95}{100} = 10.4195 ‬ m$

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From a 10.5 metre rod, an 8.05 centimetre piece is cut off. What is the length of the remaining piece?

We know that 1 m=100 cmLength of the rod=10.5 m=10.5×100=1,050‬ cmPiece of rod cut off=8.05\ cm$Remaining rod=1050−8.05=1,041.95‬ cm=1041.95100=10.4195‬ m

From a $10.5$ metre rod, an $8.05$ centimetre piece is cut off. What is the length of the remaining piece?

We know that $1 m = 100 c m$
Length of the rod $= 10.5 m = 10.5 \times 100 = 1, 050 ‬ c m$
Piece of rod cut off=8.05\ cm$
Remaining rod $= 1050 - 8.05 = 1, 041.95 ‬ c m$
$= \frac{1041.95}{100} = 10.4195 ‬ m$