Question

From a $20m$ roll of cloth, three pieces of lengths $2\frac{5}{8}m,3\frac{1}{3}m$ and $3\frac{2}{5}m$ are cut out. What length of the cloth is left?

Answer 1

Length of cloth is $20m$

$3$ pices with are:- $2\frac{5}{6}m,3\frac{1}{3}m,3\frac{2}{5}$

$\Rightarrow \frac{21}{6}m,\frac{10}{3}m,\frac{17}{5}m$

cloth left is $\Rightarrow$

$\Rightarrow 20-[\frac{21}{8}+\frac{10}{3}+\frac{17}{5}]$

$\Rightarrow 20-\frac{(21\times 15)+10\times 40+17\left(24\right)}{120}$

$20-\frac{1123}{120}$

$=\frac{2400-1123}{120}\Rightarrow \frac{1277}{120}$

$\Rightarrow 1\frac{77}{120}m$ remaining cloth