Question

Question 10

From a circular card sheet of radius 14 cm. Two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed (as shown in the adjoining figure). Find the area of the remaining sheet. $(Take\pi =\frac{22}{7})$

Answer 1

Radius of circular sheet (R) = 14 cm and Radius of smaller circle (r) = 3.5 cm
Length of rectangle (I) = 3 cm and breadth of rectangle (b) = 1 cm
According to question,
Area of remaining sheet
= Area of circular sheet - [ Area of two smaller circle + Area of rectangle ]
$=\pi R^2-\left[2\right(\pi r^2)+(l\times b\left)\right]$
$=\frac{22}{7}\times 14\times 14-[(2\times \frac{22}{7}\times 3.5\times 3.5)+(3\times 1\left)\right]$
$=22\times 14\times 2-[44\times 0.5\times 3.5+3]$
$=616-80$
$=536c{m}^2$
Therefore, the area of remaining sheet is $536c{m}^2$