Question

From a circular card sheet of radius $14cm$, two circles of radius $3.5cm$ and a rectangle of length $3cm$ and breadth $1cm$ are removed. Find the area of the remaining sheet. $(Take\pi =\frac{22}{7})$

Answer 1

The radius of circular card sheet is $14cm$. The area of the sheet is,

$A=\pi r^2$

$=\frac{22}{7}\times {\left(14\right)}^2$

$=616c{m}^2$

The area of the circle of radius $3.5cm$ is,

$A=\pi r^2$

$=\frac{22}{7}\times {\left(3.5\right)}^2$

$=38.5c{m}^2$

Since, it is given that two circles are removed, then,

$A=2\times 38.5$

$=77c{m}^2$

The area of the rectangle with length $3cm$ and breadth $1cm$ is,

$A=l\times b$

$=3\times 1$

$=3c{m}^2$

The remaining area of the circle will be,

$A=616-\left(77+3\right)$

$=536c{m}^2$