From a circular disc of radius R, a square is cut out with a radius as its diagonal. The centre of mass of remainder is at a distance (from the centre)
A
R(4π−2)
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B
R2π
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C
R(π−2)
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D
R(2π−2)
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Solution
The correct option is AR(4π−2) A1(CC1)=A2(CC2)
Side of square will beR√2 ∴CC2=A1A2(CC1) =(R√2)2πR2−(R√2)2(R2) =(R4π−2)