Consider a circular sheet with radius r and mass M. A sqaure sheet with diagonal r and mass m is cut off from it.
Assuming centre of mass of circle to be origin i.e. at 0.
Centre of mass of square sheet will be at distance of r2 from it.
Side of square =r√2
Area of square =r2/2
Assuming metal sheet as a uniform density
Mass of square m=M×r22πr2=M2π
Centre of a mass of remaining sheet =
x=M×0−(M2π×r2)M−M2π
x=−r2(2π−1)
Hence, the center of mass of the remaining part lies at a distance r2(2π−1) towards right from center of the circle.