From a group of 3 mathematicians, 4 statisticians and 5 economists, a committee of 4 is selected by lottery. The probability that the committee consists of 4 economists is

\frac{^{7} C_{4}}{^{12} C_{4}}

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\frac{^{4} C_{4}}{^{12} C_{4}}

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\frac{^{5} C_{4}}{^{12} C_{4}}

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\frac{^{13} C_{2}}{^{12} C_{4}}

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Solution

The correct option is C $\frac{^{5} C_{4}}{^{12} C_{4}}$
Total number of ways of selecting the committee is $^{12} C_{4}$
The total ways of having all 4 economists is to choose the 4 among them. Hence $^{5} C_{4}$
The probability is given by $\frac{^{5} C_{4}}{^{12} C_{4}}$

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From a group of 3 mathematicians, 4 statisticians and 5 economists, a committee of 4 is selected by lottery. The probability that the committee consists of 4 economists is

The correct option is C 5C412C4Total number of ways of selecting the committee is 12C4The total ways of having all 4 economists is to choose the 4 among them. Hence 5C4The probability is given by 5C412C4

The correct option is C $\frac{^{5} C_{4}}{^{12} C_{4}}$
Total number of ways of selecting the committee is $^{12} C_{4}$
The total ways of having all 4 economists is to choose the 4 among them. Hence $^{5} C_{4}$
The probability is given by $\frac{^{5} C_{4}}{^{12} C_{4}}$