Question

From a pack of cards two are drawn, the first being replaced before the second is drawn the probability that the first is a diamond and the second is a king will be

• A. $\frac{13}{4}$
• B. $\frac{4}{13}$
• C. $\frac{1}{52}$
• D. $52$

Answer 1

Answer: (C)

$\frac{1}{52}$

The required probability
$=\frac{{}^{13}{C}_1}{{}^{52}{C}_1}.\frac{{}^4{C}_1}{{}^{51}{C}_1}=\frac{13}{52}.\frac{4}{52}=\frac{1}{52}.$