Lines through origin perpendicular to give lines
3x2+7xy−2y2=0 is
−2x2−7xy+3y2=0
or 2x2+7xy−3y2=0.
Hence lines through A(1,1) perpendicular to given lines
are
2(x−1)2+7(x−1)(y−1)−3(y−1)2=0
or 2x2+7xy−3y2−11x−y+6=0.
Above gives the equation of lines AL and AM.