From a point at some height one body is dropped, while a second body is thrown downward with an initial velocity of 1ms−1 simultaneously in the same vertical line. The separation between these is 1.8m after a time
A
4.5s
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B
9s
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C
1.8s
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D
36s
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Solution
The correct option is C1.8s Using s=ut+12at2 And taking downward direction as positive, For the dropped body, h1=12gt2; For the thrown body, h2=1×t+12gt2=t+12gt2; h2−h1=t; So, t=1.8second ∴ (c)