wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

From a point in the interior of an equilateral triangle, perpendiculars are drawn on the three sides. The lengths of the perpendiculars are 14 cm, 10 cm, and 6 cm.
The area of the triangle is 300mcm2 where m is _______

Open in App
Solution

LetPbeanypointontheinteriorofanequilateraltriangleABC.JoinPtoall3verticesofthetriangle.Ondoingso,thetrianglegetsdividedintothreesmallertriangleswithheights6cm,10cm&14cmrespectively.Letthesideofthetrianglebey.Theareaofa=12×base×heightAreaofPAB=12×y×14=7yAreaofPBC=12×y×10=5yAreaofPCA=12×y×6=3ySo,thetotalareaoftheABC=PAB+PBC+PCA=7y+5y+3y=15y(1)Nowweknow,theareaofanequilateraltriangle=34×y2(whereyisthesideofthetriangle).(2)Henceequatingtheareas1&2weget,15y=34×y215=34×y[cancellingyfrombothsides]15×4=3×yy=603Theareaofthetriangle=15y=15×603=15×20×33=3003
226338_78122_ans.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Quadrilaterals in General
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon