From a point N on a level ground- the angle of elevation of the top of a pillar is 30- If the length of pillar is 200 m- the distance of point N from the foot of the pillar is assuming -3-1-73 -A- 298 mB- 346 mC- 400 mD- 450 m

The correct option is B 346 m Let PM be the pillar. Then, ∠PNM = 30^0 and PM = 200 m PM/MN=tan 30^0 =1/√(3) ⇒ MN = (PM×√(3)) = 200√(3) m = (200 × 1.73) m = 346 ...

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From a point N on a level ground, the angle of elevation of the top of a pillar is 30 $^{0}$ . If the length of pillar is 200 m, the distance of point N from the foot of the pillar is (assuming $\sqrt$ 3 = 1.73):

298 m

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346 m

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400 m

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450 m

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Solution

The correct option is B
346 m

Let PM be the pillar. Then, $∠$ PNM = 30 $^{0}$ and PM = 200 m

$\frac{P M}{M N}$ =tan 30 $^{0}$ = $\frac{1}{\sqrt{3}}$ $\Rightarrow$ MN = (PM $\times$ $\sqrt{3}$ ) = 200 $\sqrt{3}$ m

= (200 $\times$ 1.73) m = 346 m

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From a point N on a level ground, the angle of elevation of the top of a pillar is 300. If the length of pillar is 200 m, the distance of point N from the foot of the pillar is (assuming √3 = 1.73):

The correct option is B 346 m Let PM be the pillar. Then, ∠PNM = 300 and PM = 200 m PMMN=tan 300 =1√3 ⇒ MN = (PM×√3) = 200√3 m = (200 × 1.73) m = 346 m

From a point N on a level ground, the angle of elevation of the top of a pillar is 30 $^{0}$ . If the length of pillar is 200 m, the distance of point N from the foot of the pillar is (assuming $\sqrt$ 3 = 1.73):

The correct option is B
346 m

Let PM be the pillar. Then, $∠$ PNM = 30 $^{0}$ and PM = 200 m

$\frac{P M}{M N}$ =tan 30 $^{0}$ = $\frac{1}{\sqrt{3}}$ $\Rightarrow$ MN = (PM $\times$ $\sqrt{3}$ ) = 200 $\sqrt{3}$ m

= (200 $\times$ 1.73) m = 346 m