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Question

From a point P, perpendiculars PM,PN are drawn to x and y axes respectively. If MN passes through fixed point (a,b), locus of P, is

A
xy=ax+by
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B
xy=ab
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C
xy=bx+ay
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D
x+y=xy
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Solution

The correct option is C xy=bx+ay
∣ ∣0k1ab1h01∣ ∣=0((o,k),(a,b),(h,o)are collinear)
k(ah)+1(0bh)=0
kh=bh+ak
xy=bx+ay
58863_33795_ans_ceb02fceb68a484bbaa7cd7c01b4fa86.png

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