wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with a velocity of 35 ms1​ with respect to the ground. Calculate the recoil velocity of the rifle.


A

1 ms1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0.4375 ms1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

2.5 ms1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

0 ms1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

0.4375 ms1


Let initial velocity of bullet be u1 and initial velocity of rifle be u2.
u1 =u2 =0 (Initially bullet and rifle system was at rest)
Let, mass of rifle ,m1 = 4kg

Mass of bullet, m2 = 501000=0.05kg

Final velocity of bullet, v2 = 35 ms1
Final velocity of rifle, v1 = v

From principle of conservation of linear momentum:
Initial momentum is equal to final momentum
.
m1u1+m2u2=m1v1+m2v2
4×0+0.05×0=4×v+0.05×35
0=1.75+4v
v=0.4375 ms1

The negative sign indicates that the rifle recoils with the velocity of 0.4375 ms1.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon