Question

From a rope $11m$ long, two pieces of lengths $2\frac{3}{5}m$ and $3\frac{3}{10}m$ are cut off. What is the length of the remaining rope?

Answer 1

Given, total length of rope $=11m$

Sum of lengths of two parts

$=(2\frac{3}{5}+3\frac{3}{10})m$

$=(\frac{13}{5}+\frac{33}{10})m=\frac{26+33}{10}=\frac{59}{10}m$

Length of remaining rope $=(11-\frac{59}{10})m$

$=\frac{110-59}{10}=\frac{51}{10}m=5\frac{1}{10}m$