Question

From a rope of length $40$m $50$cm, how many pieces of rope can be cut of length $2\frac{1}{4}$m each?

Answer 1

Length of the rope$=40$m $50$cm

$=40$m $+50\times \frac{1}{100}$m $[\because 1cm=\frac{1}{100}m]$

$=40$ m$+\frac{50}{100}$m

$=(40+\frac{5}{10})$m

$=\frac{400+5}{10}$ m

$=\frac{405}{10}$m

Length of each piece of rope to be cut$=2\frac{1}{4}$ m$=\frac{9}{4}$m

Number of pieces$=\frac{\frac{405}{10}}{\frac{9}{4}}$

$=\frac{405}{10}\times \frac{4}{9}$

$=\frac{405\times 4}{10\times 9}$

$=18$

$\therefore 18$ pieces of rope can be cut of length $2\frac{1}{4}$m each.