From a set of 17 cards numbered 1 to 17, one card is drawn at random. The probability that the number on the card is divisible by 3 or 5 is

\frac{5}{17}

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\frac{6}{17}

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\frac{7}{17}

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\frac{8}{17}

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Solution

The correct option is B $\frac{7}{17}$
Numbers divisible by $3$ but not by $5$ are $3, 6, 9, 12$
Numbers divisible by $5$ are $5, 10, 15$
Thus, probability $= 7 / 17$

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From a set of 17 cards numbered 1 to 17, one card is drawn at random. The probability that the number on the card is divisible by 3 or 5 is

The correct option is B 717Numbers divisible by 3 but not by 5 are 3,6,9,12Numbers divisible by 5 are 5,10,15Thus, probability =7/17

The correct option is B $\frac{7}{17}$
Numbers divisible by $3$ but not by $5$ are $3, 6, 9, 12$
Numbers divisible by $5$ are $5, 10, 15$
Thus, probability $= 7 / 17$