Question

From a solid cylinder of height $14$ cm and base diameter $7$ cm, two equal conical holes each of radius $2.1$ cm and height $4$ cm are hollowed out . Find the volume of the remaining solid.

Answer 1

Height of cylinder $14cm$

Diameter of base $7cm$

Volume of cylinder $\pi r^{2}h\frac{22}{7}\times \frac{7}{2}\times \frac{7}{2}\times 1411\times 7\times 7539$

Radius of cone $2.1cm$

Height $4cm$

Volume of $2$ such cones $2\times \frac{1}{3}\pi r^{2}h2\times \frac{1}{3}\times \frac{22}{7}\times 2.1\times 2.1\times 444\times 0.1\times 2.1\times 436.96$

Volume of remaining solid is $539-36.96=502.04$